Question

the present age of a father is 10 years more than five times the age of his son if the father was 28 years old before two years find the present age of the father And his son​

Answer 1

Answer:

FATHER'S AGE = 30 YEARS

SON'S AGE = 4  YEARS

Step-by-step explanation:

LET FATHER'S AGE = X

∴ SON'S AGE = 5X + 10

FATHER'S AGE

FATHER'S AGE 2 YEARS BEFORE = 28

PRESENT AGE = 28 + 2

                         = 30

SON'S AGE

5X + 10 = 30

5X = 30 - 10

5X = 20

X = 20 ÷ 5

X = 4

Answer 2

Answer:

what is your question dear