Math, asked by suditi6, 6 months ago

the present age of a father is 3 times of his son after 5 years the sum of their ages would be 70 years find their present ages

Answers

Answered by dd2804726
0

Answer:

son's age 15 father's age 45

Step-by-step explanation:

let be the son's age x

then equation = x+5 + 3x+5 = 70

4x+ 10 = 70

4x= 70 / 4

= 15 x= 15

then father's age will be 3x= 3× 15 = 45

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