The present age of a father is 3 times than off his son. Five years ago he was five times as old as his son. Find their present age
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Answer:
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Answered by
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Step-by-step explanation:
Let the son's age be x.
Father's age =3x
∴3x−5=4(x−5)
or 3x−5=4x−20
or 20−5=4x−3x or x=15
After 5 years, son's age is x+5=15+5=20.
Father's age is 3x+5=45+5=50 which is 30 years more than son's age.
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