Math, asked by gupthsriram2494, 1 year ago

The present age of a father is 3 years more than three times the age of his son. three years hence, father as age will be 10 years more than twice the age of the son. find the present age of the father.

Answers

Answered by tribeking22otbgm9
311
Let father = x, son = y

x = 3y + 3

x + 3 = 2(y + 3) + 10
3y + 3 + 3 = 2y + 6 + 10
3y + 6 = 2y + 16
3y - 2y = 16 - 6
y = 10

x = 3y + 3
x = 3 × 10 + 3
x = 30 + 3
x = 33

The present age of the father is 33 years old
Answered by harshit4237
166
Hence fathers age is 33 year and son age is 10 year
Hope it helps you
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