Question

the present age of a father is 3 years more than three times of his son's age three year later, the father age will be ten years more then twice the age of of his son find the present ages​

Answer 1

SOLUTION

PRESENT

LET THE PRESENT AGE OF SON BE x

AND

PRESENT AGE OF HIS FATHER IS 3X+3.

AFTER 3 YEARS

FATHER'S AGE = 3X+6

SON'S AGE = X+3

GIVEN

FATHER'S AGE IS 10 more than 2 time of his SON'S AGE.

3X+6 = 2(X+3) +10

3X-2X+6-6=+10

X=10.

PRESENT AGE OF HIS SON'S IS 10.

PRESENT AGE OF HIS FATHER'S IS 33