Math, asked by krupadevar, 1 month ago

The Present age of a father is 3 years more than three times the age of his son . three year hence the father age will be 10 years more than twice age of the son . Determine the present age .​

Answers

Answered by vshusharma5839
0

Step-by-step explanation:

After 3 years, father's age will be (x+3) years and son's age will be (y + 3) years. Here x and y are unknowns. We have to solve the above equations for x and y. Hence, the present age of father is 33 years and the present age of son is 10 years.

Answered by vishnumurthyR
0

Answer:

Let the son's age be x

Then , according to the condition,

father's age =3x+3

3 years later:

Son's age =x+3

Father's age =3x+3+3=3x+6

According to the condition given ,  

3x+6=10+2(x+3)

3x+6=10+2x+6

x=10

Thus , the son's present age is 10 years and the father's age is  

3x+3=3×10+3=33 years.

Step-by-step explanation:

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