Math, asked by Bhaweshsingh5541, 1 year ago

The present age of a father is 3 years more than three times the age of his son.three years hence,fatherâ??s age will be 10 years more than twice the age of the son.find the present age of the father.

Answers

Answered by littyissacpe8b60
2

Son's age = a

Father age = 3 + 3a (given)

After 3 years

Son age  = a +3

Father age = (3+3a) +3 = 3a + 6

According to question

father age after 3 years = 10 + 2(a+3)

so 3a + 6 = 10 + 2(a+3)

3a + 6 =  2a + 6 + 10

a = 10

Son age = 10

Father age 3 (3x10) = 33



Answered by aj11dand11a
2

age of son=x

age of father=3.x+3

A.T.Q

3.x+6=2(x+3)+10

3.x+6=2.x+16

x=10

father age=33

Similar questions