Question

The present age of a father is 3 years more than three times the age of his son 3 years hence father age will be 10 years more than twice the age of the son determine the present ages

Answer 1

Son's present age = x

Father's age = 3 + 3x

After 3 years

son's age = x + 3

Father's age = 3 + 3x + 3 = 3x + 6   or  10 + 2(x+3)

3x + 6  = 10 + 6 + 2x

x = 10

Son's present age = 10 years old

Father's age = 3 + 3x10  = 3 + 30 = 33years old