Question

The present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice the age of the son. Find the present age of the father.

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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• At present,

Let the son's age be 'x'.

Then, father's age = 3x + 3


• After 3 years,

Son's age = x + 3

Father's age = 3x + 3 + 3 = 3x + 6


• But, according to the question, after 3 years, father's age is 10 years more than twice son's age.

=> 3x + 6 = 2(x + 3) + 10

=> 3x + 6 = 2x + 6 + 10

=> 3x - 2x = 6 + 10 - 6

=> x = 10


• Hence, son's present age = x = 10 years.

• And, father's present age = 3x + 3
= 3 × 10 + 3
= 30 + 3
= 33 years


$<marquee>Hence, your answers are 10 years and 33 years.</marquee>$
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Thank you.. ;-)