Math, asked by vickey89, 1 year ago

the present age of a father is 3 years more than three times the age of the son 3 years later father age will be 10 year more than twice age of the son their present age are?
HELP ME FRIEND'S​

Answers

Answered by pratyush4211
1

Let Present Age of Son=x years

Then Father is 3 years more than 3times the son age

Father Present Age=3x+3 years

After 3 years

Son Age=(x+3) years

Father Age=(3x+3+3)=(3x+6) years

Now Father Age is also 10 years more. twice the age of son

Then,

2(x+3)+10=3x+6

2x+6+10=3x+6

2x+16=3x+6

2x-3x=6-16

-x=-10

x=10

Son age=x=10 years

Father=3x+3=3×10+3=33 years

Present Age of Son=x=3 years

Father=3x+3

\boxed{\mathbf{\huge{Son\implies10\:years}}}

\boxed{\mathbf{\huge{Father\implies33\:years}}}

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