The present age of a father is 4 years more than treble the age of his son.If the father was 35 years old before five years,find the present age of father and his son.
Answers
Answered by
18
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• At present,
Let the son's age be 'x'.
Then, father's age = 3x + 4
• 5 years ago from now,
Son's age = x - 5
Father's age = 3x + 4 - 5 = 3x - 1
• But, according to the question, five years ago, father's age was 35 years.
=> 3x - 1 = 35
=> 3x = 35 + 1
=> 3x = 36
=> x = 36/3
=> x = 12
• Hence, present age of the son = x = 12 years.
• And, present age of the father = 3x + 4
= 3 × 12 + 4
= 36 + 4
= 40 years.
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Thank you.. ;-)
Answered by
8
solutions :-
Let the son's age be x
Then, father's age = 3x + 4
5 years ago
Son's age = x - 5
Father's age = 3x + 4 - 5 = 3x - 1
A/q
five years ago, father's age was 35 years.
=> 3x - 1 = 35
=> 3x = 35 + 1
=> 3x = 36
=> x = 36/3
=> x = 12
Hence,
present age of the son = x = 12 years.
present age of the father = 3x + 4
=> 3 × 12 + 4
=> 36 + 4
=> 40 years.
Thank
Let the son's age be x
Then, father's age = 3x + 4
5 years ago
Son's age = x - 5
Father's age = 3x + 4 - 5 = 3x - 1
A/q
five years ago, father's age was 35 years.
=> 3x - 1 = 35
=> 3x = 35 + 1
=> 3x = 36
=> x = 36/3
=> x = 12
Hence,
present age of the son = x = 12 years.
present age of the father = 3x + 4
=> 3 × 12 + 4
=> 36 + 4
=> 40 years.
Thank
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