Question

The present age of a father is equal to the Sum
of ages of his 5 children. 12 years later sum of ages of his children will be twice the age of his father find the age of father​

Answer 1

$\huge\bf\underline{Answer}$

The age of the father is 36 years respectively.

Solution :-

Given,

Age of father = Sum of the ages of his 5 children

Let the age of father be x

and the Sum of the children's age be y

Hence, x = y

Twelve years later,

Age of father = (x + 12) years

Age of childrens = (y + 5.12) years

= (y + 60) years

According to the question,

=> 2(x + 12) = (y + 60)

=> 2x + 24 = y + 60

=> 2x = y + 60 - 24

=> 2x = y + 36

(As, x is equal to y. Therefore, Putting x in the place of y)

=> 2x = x + 36

=> 2x - x = 36

=> x = 36

Hence, the age of the father is 36

Answer 2

Answer:

The age of father is 36 years.

Step-by-step explanation:

Given Problem:

The present age of a father is equal to the Sum of ages of his 5 children. 12 years later sum of ages of his children willbetwice the age of his father find the age of father​.

Solution:

To Find:

The age of father.

-------------------------

Method:

Let the age of father will be x years.

Let the age of children will be y years.

Now,

After 12 years,

Agee of father = (x+12) years

Sum of ages of 5 children =  (y + 5.12) years  = (y + 60) years

According to given problem:

x = y              (Equation)1

⇒ 2(x + 12) = (y + 60)

⇒ 2x + 24 = y + 60

⇒ 2x = y + 60 - 24

⇒ 2x = y + 36

We know that,

x = y

So, We can put x in the place of y

⇒ 2x = x + 36

⇒ 2x - x = 36

⇒ x = 36 ..........................(Present age)

Therefore,

The age of father is 36 years.