The present age of a father is equal to the sum of ages of his 5 children. 8 yrs hence the sum of ages of of his children will be 16 yrs less than twice the age of their father. Find the present age of the father.
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Let us assume that the present age of Father is x years
and the ages of his sons are a, b, c, d, and e years respectively
Given:
x = a + b + c + d + e -------------1
Also given,
8 years hence
a + 8 + b + 8 + c + 8 + d + 8 + e + 8 = 2 (x + 8) - 16
a + b + c + d + c + 40 = 2x + 16 - 16
a + b + c + d + c + 40 = 2x
Substitute the value from equation 1, i. e. a + b + c + d + e = x
x + 40 = 2x
x = 40 years
The present age of Father is 40 years.
and the ages of his sons are a, b, c, d, and e years respectively
Given:
x = a + b + c + d + e -------------1
Also given,
8 years hence
a + 8 + b + 8 + c + 8 + d + 8 + e + 8 = 2 (x + 8) - 16
a + b + c + d + c + 40 = 2x + 16 - 16
a + b + c + d + c + 40 = 2x
Substitute the value from equation 1, i. e. a + b + c + d + e = x
x + 40 = 2x
x = 40 years
The present age of Father is 40 years.
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