Math, asked by secret18black, 7 months ago

the present age of a father is four times the age of his son .after 10 years the age of the father will become three times the age of his son find their present age

Answers

Answered by suman7300676255
0

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Answered by Anonymous
92

  \large\underline{\underline{\mathfrak{\color{blue}{Given :-}}}}

  • the present age of a father is four times the age of his son .

  • after 10 years the age of the father will become three times

  \large\underline{\underline{\mathfrak{\color{blue}{To  \: Find :-}}}} \\

  • find their present age

  \large\underline{\underline{\mathfrak{\color{blue}{Solution :-}}}} \\

let the father's age be 4x and son's age be x

A fter 10 years their age

  \sf \to \:  4x + 10 = 3 \times (x+ 10) \\  \\ </p><p>     \sf  \to \: 4x+10= 3x +30 \\  \\ </p><p>    \sf \to 4x -3x = 30-10 \\  \\  \sf \to</p><p>     \red{x= 20 }\\  \\

father age 4x

Then 4 × 20

= 80 Year

 \therefore  \: \underline {\sf son's \:  Present  \: Age   \:  \pink{20}}

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