The present age of a father is square of the age of his son. After six years, the age of the
father would be 3 1/4 times the age of the son. The present age of the father is
36
42
48
54
Answers
Answered by
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Step-by-step explanation:
Let's assume the present age of the son to be x years
So, the present age of the father = 2x
2
years.
Eight year ago,
Son's age = (x+8) years
Father's age = (2x
2
+8) years
From the question, it's given that eight years hence, the age of the father will be 4 years more than three times the age of the son.
2x2+8=3(x+8)+4
2x2+8=3x+24+4
2x2−3x−20=0
2x2−8x+5x−20=0
2x(x−4)+5(x−4)=0
(x−4)(2x+5)=0
x=4,−5/2
As, age cannot be negative, x=4 is considered.
Therefore,
The present age of son = 4 years
The present age of the father = 2(4)
2
years = 32 years
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