Math, asked by sethupathywastemail, 6 months ago


The present age of a father is square of the age of his son. After six years, the age of the
father would be 3 1/4 times the age of the son. The present age of the father is

36

42

48

54​

Answers

Answered by akshrajain30aug2007
1

Step-by-step explanation:

Let's assume the present age of the son to be x years

So, the present age of the father = 2x

2

years.

Eight year ago,

Son's age = (x+8) years

Father's age = (2x

2

+8) years

From the question, it's given that eight years hence, the age of the father will be 4 years more than three times the age of the son.

2x2+8=3(x+8)+4

2x2+8=3x+24+4

2x2−3x−20=0

2x2−8x+5x−20=0

2x(x−4)+5(x−4)=0

(x−4)(2x+5)=0

x=4,−5/2

As, age cannot be negative, x=4 is considered.

Therefore,

The present age of son = 4 years

The present age of the father = 2(4)

2

years = 32 years

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