Question

. The present age of a father is the square of his sons present age . In 7 years the

Father will be four times his sons age , find present ages , taking the sons present

. age as ‘x’.​

Answer 1

Answer:

Son's age = 7 years, Father's age = 49 years

Step-by-step explanation:

sons present age = x

Father's age = x^2

after 7 years sons age =4( x + 7)

after 7 years father's age = x^2 + 7

$4x + 28 = {x}^{2} + 7$

${x}^{2} - 4x - 21 = 0$

${x}^{2} - 7x + 3x - 21 = 0$

$x(x - 7) + 3(x - 7) = 0$

$(x - 7)(x + 3) = 0$

Either X - 7 = 0 or, X + 3 = 0

X = 7 or, X = - 3

Value of X can never be in minus. Reject -3.

Present age of Son = 7 years

Father's present age = 49 years.

Kindly mark it as brainliest.