Question

The present age of a father is the square of his sons present age . In 7 years the

Father will be four times his sons age , find present ages , taking the sons present

. age as ‘x’.​

Answer 1

Answer:

Step-by-step explanation:

Let present age of son be x

Age of father = x²

Age of son after four years = x+4

Age of father after four years = x²+4

Given 4(x+4) = x² + 4

4x + 16 = x² + 4

x² - 4x - 12 = 0

x² -6x +2x - 12 = 0

x(x-6)+2(x-6)=0

(x+2)(x-6) = 0

x = -2 or 6

Age cannot be negative .

So present age of son = 6

Father's present age = 6² = 36.