Question

The present age of a father is three times than that of his son. five years ago he was five times as old as his son. Find their present age.​

Answer 1

Son's present age = x

Father's present age = 3x

son's age 5 years ago = (x-5)

fathers age 5 years ago = (3x-5)

: 5(x-5) = 3x-5

: 5x - 25 = 3x-5

: 5x - 3x = -5+25

: 2x = 20

: x= 10

therefore,

sons present age = x = 10

fathers present age = 3x= 3*10=30

sons age = 10

Father age = 30

.

Answer 2

Step-by-step explanation:

The present age of a father is equal to the sum of the ages of his 5 children. 12 years hence, the sum of the ages of his children will be twice the age of their father.