Question

The present age of a father is three times
the age of his son. Aber 20 years, the age
of the father will become two time the age​

Answer 1

Step-by-step explanation:

Let's assume the age of his son as x years.

His fathers age will be 3x years

After 20 years

Father age = (3x + 20)

His sons age = x + 20

According to the question :

➡ 2(x + 20) = 3x + 20

➡ 2x + 40 = 3x + 20

➡ 40-20 = 3x - 2x

➡ 20 = x

Therefore

Sons age = 20 years

Father age = 60 years

Answer 2

Correct Question:

The present age of a father is three times  the age of his son. After 20 years, the age  of the father will become two time the age​ of son. Find their present ages.

Solution:

Let the present age of father be 'f'

Present age of son be 's'

According to the question,

f = 3s     →  →  →  [Equation 1]

After 20 years,

Father's age = f + 20

Son's age = s + 20

Now,

(f + 20) = 2(s + 20)

⇒ f + 20 = 2s + 40

⇒ f - 2s = 40 - 20

⇒ 3s - 2s = 40 - 20        (∵ f = 3s)

⇒ s = 20 years

Substitute value of s to find the value of f

f = 3s

⇒ f = 3 × 20

⇒ f = 60 years

Final Answer:

• Son's age = 20 years
• Father's age = 60 years