Math, asked by rehanbhat05, 11 hours ago

The present age of a father is three times the age of his son. After 20 years, the age of the father
become two times the age of his son.
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Answers

Answered by pihu26march
2

Answer:

Step-by-step explanation :

let the son's age be x

father's age = 3x

After 20 years

son's age = x+20

Father's age = 3x+20

3x+20=2 (x+20)

3x+20=2x+40

x= 20 son's age now

father age = 3x= 20×3= 60

Father's age now = 45 years

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