Question

The present age of a father is three years more than three times the age
of his son. Three years hence the father's age will be 10 years more than
twice the age of the son. Determine their present ages.​

Answer 1

Answer:

Father's age= 24 years

Son's age = 7 years

Step-by-step explanation:

Let the age of father be x and age of son be y.

A/C to the 1st condition

x=3y+3. .......(1)

A/C to the 2nd condition

x=10+2y. ..........(2)

put (2) in (1)

3y+3=10+2y

y=7

put y=7 in equation (1)

x=3(7)+3

x=24

Therefore the age of father is 24 years and that of son is 7 years.

Answer 2

Given :-

The present age of a father is three years more than three times the age of the son . Three years hence father's age will be 10 years more than twice the age of the son .

To Find :-

Present ages

Solution :-

Let the age of son be x and father age will be 3x + 3

After 3 years

Age of son = x + 3

Age of father = 3x + 3 + 3 = 3x + 6

Now

ATQ

3x + 6 = 10 + {2(x + 3)}

3x + 6 = 10 + 2x + 6

3x + 6 = 16 + 2x

3x - 2x = 16 - 6

x = 10

Age of son = 10 years

Age of father = 3(10) + 3 = 33 years