Math, asked by AnumehPatil, 10 months ago

The present age of a father is three years more than three times the age of his son. Three years hence the father’s age will be 10 years more than twice the age of the son. Determine their present ages.

Answers

Answered by keshav4047
2

Answer:

Let the son's age be x. Thus, the son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.

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