Question

The present age of a father is three years more than three times the age of the son . Three years hence father's age will be 10 years more than twice the age of the son . Determine their present ages.

Answer 1

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Answer 2

Given :-

The present age of a father is three years more than three times the age of the son . Three years hence father's age will be 10 years more than twice the age of the son .

To Find :-

Present ages

Solution :-

Let the age of son be x and father age will be 3x + 3

After 3 years

Age of son = x + 3

Age of father = 3x + 3 + 3 = 3x + 6

Now

ATQ

3x + 6 = 10 + {2(x + 3)}

3x + 6 = 10 + 2x + 6

3x + 6 = 16 + 2x

3x - 2x = 16 - 6

x = 10

Age of son = 10 years

Age of father = 3(10) + 3 = 33 years