Math, asked by AvinabaMukherjee, 1 month ago

The present age of a father is thrice his son's age.
After 15 years, the difference of their ages will be 30
years. What are their present ages?​

Answers

Answered by ibrahimtrcg2020
6

Answer:

Step-by-step explanation:

Let x be son's present age ,then father's present age =3x

After 15 years

Son's age =x+15

Father's age =3x+15

(3x+15) - (x+15) =30

3x+15-x-15 =30

2x = 30

∴x=30÷2 =15

Son's present age =15

Father's present age = 3x =3×15 =45

Check

Present son's age = 15

Present father's age = 45

After 15 years

Son's age =15+15 =30

Father's age = 45+15 =60

Age difference =60-30 =30

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