The present age of a father is twice that of his son. Eight years hence their ages would be 7 : 4 find the son's present age
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If present age of man and son is x and y years respectively. Then by first condition,
x=2y which gives x-2y=0
And by second condition,
(x+8)/(y+8)=7/4 which gives 4x-7y=24
Hence after solving above two equations,
x=48 and y=24
which are present ages of man and son resp.
x=2y which gives x-2y=0
And by second condition,
(x+8)/(y+8)=7/4 which gives 4x-7y=24
Hence after solving above two equations,
x=48 and y=24
which are present ages of man and son resp.
ujjalneog:
Thank u very much
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