Math, asked by sweet12345678, 1 year ago

the present age of a father's is 3 years more than three times the age of his son.three years hence,father's age will be 10 year more than twice the age of the son.find the present age of the father. with full soluction

Answers

Answered by Shreya142931
91
Let the present age of son be x.
Present age of father= 3+3x
After 3 years,
Age of son = 3+x
Age of father= 3+3+3x
=6+3x
6+3x = 10+ 2(3+x)
6+3x=10+6+2x
6+3x=16+2x
x=10
Present age of son = 10 years
Present age of father= 3+3x=3+30
=33years
Hope it helps:)
Answered by VishalSharma01
179

Answer:

Step-by-step explanation:

Given :-

The present age of a father's is 3 years more than three times the age of his son.

Three years hence,father's age will be 10 year more than twice the age of the son.

To Find :-

The present age of the father.

Solution :-

Let the son's present age be x years.  

According to the question

Father's present age = (3x + 3) years  

(3x + 3 + 3) = 2 (x + 3) + 10  

3x + 6 = 2x + 16  

x = 10.  

Father's present age = (3x + 3)

= ((3 x 10) + 3) years

= 33 years.

Hence, father's present age is 33 years.

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