Question

the present age of a is 4 years less than twice the present age of B. B's present age is 6years more than twice his age 15years ago.find the difference of there ages?​

Answer 1

Let the present age of B be x years

⇒ Present age of A is 2x−4 years

x=2(x−15)+6

x=2x−30+6

24=x

∴ A's present ages =2×24−4=48−4=44 years

∴ Difference between their ages =44−24=20 years