Question

The present age of A is 4 years less than twice the present age of B. B's present age is 6 years more than twice his age 15 years ago. Find the difference. ​

Answer 1

Answer:

difference is A-B = 44-24 = 20 years

Step-by-step explanation:

A present age is 44 years

B present age is 24 years

Answer 2

➠ Given :-

➵ Present age of A is 4 years less than twice the present age of B.

➵ B's present age is 6 years more than twice his age 15 years ago.

➠ Assumption :-

➵ Let the present age of A be a.

➵ Present age of B be b.

➠ Solution :-

❒ According to the Question :-

➵ a = (2b - 4)

we know,

⟶ Age of B, 15 years ago will be (b - 15).

➵ b = 2(b - 15) +6

⟹ b = 2b - 30 + 6

⟹ b = 2b - 24

✪ The Difference of their ages:-

⇒ a - b [∵Substituting the values]

⟹ (2b - 4) - (2b - 24)

⟹ 2b -4 -2b +24

∴ 20

➠ Answer :-

❒ Thus, the required age difference is 20 years.