Question

the present age of A is twice the age of B. 18 years ago the age of C is half of the age of B 6years hence. if the average age of A B C is 42.find the age of A, 9years hence???​

Answer 1

Answer:

Let age of A be a.

Let age of B be b.

Let age of C be c.

a, b, c are the ages 3 years ago.

Three years ago, average of a and b is 18.

ie,

(a+b)/2=18

or,(a+b)=36

Now, C joins. Average is 22, ie.,

(a+b+c)/3=22

or,(a+b+c)=66

We know, (a+b)=36

So,

(36+c)=66

or,c=66−36=30

But that was 3 years ago.

So, current age of C is 30+3=33.

Step-by-step explanation:

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