Question

The present age of a man is 3 times of his son.Ten years ago he was 5 times as old as his son,then age of the son 3 years later (in years) is

Answer 1

Son present age=x

Man present age=3x

10year ago

Son age =x-10

Man age=3x-10

A/q

(3x-10)=5(x-10)

5x-3x=-10+50

2x=40

X=20

Son present age=20

3year hence=20+3=23