The present age of a man is 3 times that of his son. Ten years ago, he was 5 times as old as his son,
then age of the son 3 years later (in years) is
Answers
Answer:
3 years later, the age of the son will be = 23years
Step-by-step explanation:
let the son's age = x years
=> given, the present age of the man = 3x years
also, given that 10years ago, he is 5 times his son's age
=> x-10 = 5(x-10)
ie., 5(x-10) = 3x-10
=> 5x-50 = 3x-10
=> 5x-3x = 50-10
=> 2x = 40
=> x = 20
ie., the son's present age = 20years
and 3 years later he will be = 20+3 years
= 23years
verification:
we have present age of son = 20yrs
=> the fathers present age = 3(20) = 60years
10years before,
age of son = 20-10 = 10years
and the age of father = 60-10
= 50 years (which is 5 times the age of son)
=> 10 years ago, age of the father = 5 times the age of son at that time.
hence verified.