Question

The present age of a man is 3 years more than three times the age of his son. Three years hence, the man's age will be 10 years more the than twice the age of his son. If the man's present age is x years and son's present age is y years. PLZ FAST

Answer 1

Answer:

Let the present age of the son of that man be x years

So, age of man will be 3 times of x + 3 years

⇒ ( 3x + 3 ) years

Given, 3 years hence man's age will be 10 years more than twice the age of his son

Age of man 3 years hence = Present age + 3 years

= ( 3x + 3 )years + 3 years

= ( 3x + 6 ) years ------ : ( 1 )

Age of son = Present age + 3 years

= x years + 3 years

= ( x + 3 ) years ------: ( 2 )

According to the questions : -

Three years hence the mans age will be 10 years more than twice the age of his son

Man's age 3 years hence = 10 years more than the twice of his son's age

From ( 1 ) & ( 2 )

⇒ ( 3x + 6 ) years = 2( x + 3 ) years + 10 years

⇒ ( 3x + 6 ) = 2( x ) + 2( 3 ) + 10

⇒ 3x + 6 = 2x + 6 + 10

⇒ 3x - 2x = 10 + 6 -6

⇒ x = 10

∴ Present age of man's son = x years = 10 years

∴ Present age of man = 3x + 3 = 3( 10 ) + 3 years

Present age of man = 33 years

Answer 2

Answer:

Given that the man is 3 years more than three times the age of his son. So, the present age of the man = 3x + 3. ⇒ Age of son = x + 3. ⇒ Age of man = 3x + 6.

Explanation:

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