Question

The present age of a man is double the age of his son. After 8 year the ratio
of their ages will be 7:4. Assuming the present age of the son to be x years,
obtain an equation for the statement. Also, find the present ages of the man
and his son.​

Answer 1

Answer:

24 and 48 years

Step-by-step explanation:

present age of son=x

present age of father=y=2x

equation after 8 years, (y+8)*4=7*(x+8)

x=24

y=48

Answer 2

Answer:

The equation is 4y - 7x = 24

The age of the man is 48 years

and of the son is 24 years

Step-by-step explanation:

Let us assume the age of the son be x years

and let the age of the man be y

Since , the age of the man is double his son , so age of the man is

y = 2x

According to Question

(2x + 8 ): (x + 8) = 7:4

$\frac{y+ 8}{x + 8} = \frac{7}{4} \\ \implies4y + 32 = 7x + 56 \\ \implies \: 4y-7x= 56 - 32 \\ \implies4y - 7x = 24$

It is the equation for the above questioned statement .

Now ,

$4(2x) - 7x = 24 \: \: (since \: y = 2x) \\ \implies8x - 7x = 24 \\ \implies \: x = 24$

The age of the son is 24 years

So

$y = 2 \times 24 \\ \implies \: y = 48$

Therefore, the age of the man is 48 years