Math, asked by Anonymous, 3 months ago

The present age of a man is five times the age of his son. Five years ago,
the age of the man was ten times the age of his son at that time. How old
is the man at present ?
(a) 45 years
(6) 48 years
(c) 49 years
(d) 52 years
(e) None of these​

Answers

Answered by simranjeetkaur6366
3

Answer:

a) 45years

Step-by-step explanation:

Let F and S be the current ages of the father and son respectively.

From the first statement: F = 5 S

From the second statement:

F - 5 = 10(S - 5).

So F - 5 = 10S - 50 or F = 10S - 45

Combining this last equation with the first:

5S = 10S - 45

=>> 45 = 5S (adding 45 to both sides and subtracting 5S from both sides)

Dividing by 5 gives us 9 = S

So the father is 45 and the son is 9.

Five years ago they were 40 and 4.

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