Question

The present age of a man is seven times the present
age of his son. Two years ago, the age of the man
was eleven times the age of the son. Find the pres-
ent age of the man (in years).​

Answer 1

Answer:

present age of the MAN=35 years and his SON =5 years

2years ago  age of the man =33 years and his son = 3 years

Step-by-step explanation:

Answer 2

SOLUTION:-

Given:

•The present age of a man is seven times the present age of his son.

•Two year's ago, the age of the man was eleven times the age of the son.

To find:

The present age of the man.

Explanation:

We have,

•The present age of the man is 7R.

•The present age of the son is R

2 years ago,

The age of the man is 7R -2 years

The age of the son is R -2 years.

According to the question:

=) 7R -2 = 11(R-2)

=) 7R -2 = 11R -22

=) 7R -11R= -22 +2

=) -4R = -20

=) R = -20/-4

=) R= 5 years

Hence,

The man's age is 7R

=) 7 × 5

=) 35 years