Question

the present age of a man is three times that of his son.six years ago the age of the man was four times that of his son.find the ratio of their ages 6 years later.

Answer 1

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Answer 2

$let \: son \: age \: be \: x \\ father \: age = 3x \\ 6year \: ago \\ son = x - 6 \\ father = 3x - 6 \\ according \: to \: question \\ the \: father = 4(x - 6) \\ 3x - 6 = 4x - 24 \\ 4x - 3x - 24 + 6 = 0 \\ x - 18 = 0 \\ x = 18s \\ son \: age \: is \: 18 \: years \: and \: father \: is54years \\ 6year \: later \\ son \: age = 18 + 6 \\ = 24 \\ father \: age = 54 + 6 \\ = 60 \\ \: \frac{father \: age}{son \: age} \\ = \frac{60}{24} \\ = \frac{5}{2}$
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