Question

The present age of a man is twice that of his son. 8 years hence , their ages will be in ratio of 7: 4. find theier pren=sent ages.

Answer 1

Answer:

24,48

Step-by-step explanation:

(2x + 8)/(x + 8) = 7/4

x = 24

their present ages

son x=24 & father =2x =2×24=48