Question

the present age of a man is twice that of his son. 8 years hence, their ages will be in the ratio 7: 4 find the present ages

Answer 1

son's age=24
father's age=48

Answer 2

Answer:

Step-by-step explanation:

Given :-

The present age of a man is twice that of his son.

8 years hence, their ages will be in the ratio 7: 4.

To Find :-

The Present Ages

Solution :-

Let present age of son = x year

Let the age of his father = 2x  

8 years hence,  Age of son = (x + 8) years

and age of father = (2x + 8) years  

According to the condition,

⇒ (2x+8)/(x+8) = 7/4

⇒ 8x + 32 = 7x + 56  

⇒ 8x – 7x = 56 – 32  

⇒ x = 24

Present age of son = 24 years

and age of father = 2x = 2 x 24 = 48 years

Hence age of man is 48 years and age of his son is 24 years.