Question

the present age of a man is twice that of his son .Eight years hence, their ages will be in the ratio 7:4. Find their present ages.​

Answer 1

Answer:let's son's age be x then

Father's age willbe 2x

After 8 years,

Father age = 2x +8 and

Son's age =x+8

In ratio...

(2x+8) /(x+8) =7/4

Cross multiplication..

4(2x+8) =7(x+8)

8x+32=7x+56

Rearranging...

8x-7x=56-32

x=24

Present ages

Son's age =24 years

Father's age=2x=2×24=48 years

Answer 2

Answer:

Step-by-step explanation:

Present age:

son's age =x

man's age=2x

After 8 years:

man's age=2x+8

son's age=x+8

man's age ratio=7

son's age ratio=4

2x+8÷x+8=7÷4

Cross Multiplication

8x+32=7x+56

x=24

son's age=24 years

man's age=48 years