Question

the present age of a man is twice that of his son .Eight years hence their ages will be the ratio 7 is to 4 find their present ages

Answer 1

Let son's age=x
Father's age=2x
(2x+8):(x+8)=7:4
Cross multiplying...
8x+32=7x+56
x=24
Son's age=24 years
Father's age=48 years

Answer 2

let the man's age = x
let the son's age  = y
x = 2y
(x + 8)/(y + 8) = 7/4
8y + 32 = 7y + 56
y = 56 - 32
   = 24 Years
x = 48 Years. ANSWER.
thanks...