Math, asked by linearequations, 1 year ago

The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7:4. Find their present ages.

Answers

Answered by yrutwik
5
Let x be the age of man And y be the age of son Given x=2y (x+8)/(y+8)=7/4 By solving it we can find that x=48 y=24
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