The present age of a man is twice that of his son. Eight years hence there age will be in the ratio 7:4 find their present ages.
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Answer: After 8 years, their ages will be (x + 8) years and (2x + 8) years respectively. Given, After 8 years, the ratio of their ages will be 7 : 4. ⇒ x = 24 years. Thus, the present age of the son is 24 years.
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Answer:
Let the present age of the son be x years.
Then, the father's age = 2x years.
After 8 years, their ages will be (x + 8) years and (2x + 8) years respectively.
Given, After 8 years, the ratio of their ages will be 7/4 .
As per given conditions,
(x + 8)/(2x + 8) - 4/7
=>7x+56=8x+32
=> x=24 years.
Thus, the present age of the son is 24 years.
Then, the father's age = 48 years.
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