Question

The present age of a man is twice that of his son. Eight year hence, their ages will be in the ratio 7:4.Find their present ages.

Answer 1

Hii !!

Here is your answer,,

Present age of man = x ( years )
present age of his son = y ( years )

As per given that present age of man is twice of his son.

x = 2y. .................(1)

After 8 years..,,

age of man will be = x + 8

age of his son will be = y + 8

$\frac{x + 8}{y + 8} = \frac{7}{4} \\ \\ 4x + 32 = 7y + 56 \\ \\ 4x - 7y = 24 \\ \\ from \: eq.(1) \: \: \: \: \: we \: \: get.. \\ \\ 4(2y) - 7y = 24 \\ \\ 8y - 7y = 24 \\ \\ y = 24 \\ \\ put \: value \: of \: (y) \: in \: eq.(1) \\ \\ x = 2(24) \\ \\ x = 48$


present Age of man is 48 years..

present Age of his son is 24 years.

Hope it helps ...

THANKS.:D

Answer 2

Hi,

Please see the attached file!


Thanks