the present age of a man is twice that of his sons age. eight years hence, their ages will be in the ratio 7:4. find their present age
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son's age is 24 years and man's age is 48 years
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Answer:
Step-by-step explanation:
Let man's age be x
Son's age be y
Atq,
X =2y
Eight years hence,
X+8/y+8 = 7/4
2y+8/y+8=7/4. (X=2y)
8y+32=7y+56. ( By cross multiplication )
Y= 24
X= 48. (X=2y)
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