Math, asked by ommaditya, 1 year ago

the present age of a man is twice that of his sons age. eight years hence, their ages will be in the ratio 7:4. find their present age

Answers

Answered by Harshscigen
1

son's age is 24 years and man's age is 48 years

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Answered by yuvijain701
24

Answer:


Step-by-step explanation:

Let man's age be x

Son's age be y

Atq,

X =2y

Eight years hence,

X+8/y+8 = 7/4

2y+8/y+8=7/4. (X=2y)

8y+32=7y+56. ( By cross multiplication )

Y= 24

X= 48. (X=2y)

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