Question

= The present age of a mother and son is in the ratio 8:1. The difference in their ages after 3 years will be 4 times the age of the son. Find the ratio of their ages 3 years ago? (Age 1) Select one: O a. 8:1 O b. 29:1 O c. 7:2 O d. 5:1​

Answer 1

Answer:

Step-by-step explanation:

Metamorphic rocks were once igneous or sedimentary rocks, but have been changed (metamorphosed) as a result of intense heat and/or pressure within the Earth's crust. They are crystalline and often have a “squashed” (foliated or banded) texture.

Answer 2

The ratio of ages of ages of mother and son three years ago = 29:1

Given,

The ratio of the present age of mother and son = 8:1

The difference in their ages after 3 years = 4 × the age of the son

To Find,

The ratio of ages of ages of mother and son three years ago

Solution,

Let the present age of the mother be x,

and the present age of the son be y.

We have been given that the present age of a mother and son is the ratio 8:1.

⇒ x:y = 8:1

⇒ x/y = 8/1

⇒ x = 8y

Let this be equation (1)

Further, we have been given that the difference in their ages after 3 years will be 4 times the age of the son.

The age of mother after three years = x + 3

The age of mother after three years = y + 3

⇒ x + 3 - (y + 3) = 4(y + 3)

⇒ x + 3 - y - 3 = 4y + 12

⇒ x - y = 4y + 12

⇒ x = 4y + y + 12

⇒ x = 5y + 12

Let this be equation (2)

Equating equation (1) in equation (2), we get the following:

⇒ 8y = 5y + 12

⇒ 8y - 5y = 12

⇒ 3y = 12

⇒ y = 4

Substituting the value of y in equation (1), we get the following:

⇒ x = 8 × 4

⇒ x = 32

Therefore, the current ages of the mother is 32 years and the son is 4 years.

The age of mother three years ago = 32 - 3 = 29

The age of son three years ago = 4 - 3 = 1

Hence, the ratio of ages of ages of mother and son three years ago = 29:1

Read more on Brainly.in:

1. brainly.in/question/9703744

2. brainly.in/question/24639774

#SPJ2