Question

the present age of a mother is twice that of her daughter eight years later their ages would be 7 ratio 4 find the daughter present each​

Answer 1

Answer:

Step-by-step explanation:

let daughter be x

2x + 8/x +8 = 7/4

4(2x + 8)=7(x + 8)

8x + 32 = 7x +8

8x - 7x = 32 - 8

x = 26 daughter

2x = 26 * 2=52