Question

The present age of a son is half the present age of his father. Ten years ago, the father was thrice as
old as his son. What are their present ages?

Answer 1

Answer:

present age of father = 40

present age of son = 20

Step-by-step explanation:

let the present age of father be x

son's present age will be 1/2 x

ten years ago

age of father = x - 10

age of son = 1/2 x - 10

ten years ago father's age was thrice of son's age

x - 10 = 3(1/2x - 10)

$x - 10 = \frac{3}{2} x - 30 \\ \frac{3}{2} x - x = - 10 + 30 \\ \frac{3x - 2x}{2} = 20 \\ \frac{x}{2} = 20 \\ x = 20 \times 2 \\ x = 40$

present age of father = x = 40

present age of son = 1/2 x = 1/2 × 40 = 20

hope you get your answer

Answer 2

Answer :- 40 and 20 years.

Given that :-

• The present age of a son is half the present age of his father. Ten years ago, the father was thrice as
• The present age of a son is half the present age of his father. Ten years ago, the father was thrice asold as his son.

To find :-

• Their present ages.

Solution :-

Let the present age of father be 'x' years.

Present age of a son = Half the present

age of his father = (1/2) * x = x/2 years.

Age of father ten years ago = (x - 10) years

Age of son ten years ago = {(x/2) - 10} years.

Now ,

•°•Age of fathe ten years ago = thrice the Age of son ten years ago.

⇒ (x - 10) = 3{ (x/2) - 10 }

⇒ x - 10 = 3 { (x - 20)/2 }

⇒ x - 10 = 3(x - 20)/2

⇒ 2(x - 10) = 3(x - 20)

⇒ 2x - 20 = 3x - 60

⇒ - 20 + 60 = 3x - 2x

⇒ 40 = x

⇒ x = 40

Present age of father = x = 40 years

Present age of son = (40/2) = 20 years