The present age of a son is half the present age of his father. Ten years age, the father was thrica as old his son. what are their present ages
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Answer:
The present age of son is half the present age of his father.
Let the present age of the father be 2x.
Therefore present age of the son = 2x/2 = x years
ATQ,
10 years ago, father's age was thrice as old as his son.
= 3(x - 10) = 2x - 10
= 3x - 30 = 2x - 10
= 3x - 2x = -10 + 30
= x = 20
Hence their present ages are :-
Father's present age = 2x = 40 years
His son's present age = x = 20 years
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Step-by-step explanation:
Answer. Let the present age of father be 'a'. So, the present age of son be 'a/2'. So, Age of son ten years ago = (a - 10)/2.
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