Question

The present age of a son is half the present age of his father,ten year ago, the father was thrice as old as his son,what is their present age

Answer 1

Answer:

• Let the present age of son be x and that of father be 2x
• Ten years ago,
• Age of son is x-10
• Age of father is 2x-10
• ATP,
• 2x-10=3(x-10)
• 2x-10=3x-30
• -x = -20
• x=20
• 2x = 40
• The present age of son is 20 and that of father is 40

Step-by-step explanation:

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Answer 2

Required Answer:-

Given:

• The present age of a son is half the present age of his father.
• Ten years ago, the father was thrice as old as his son.

To find:

• The present age of son and man.

Solution:

★ Let the present age of son be x years.

★ Let the present age of father be y years.

Therefore,

➡ x = y/2 (Half the age of father)

➡ 2x = y

➡ 2x - y = 0 .......(i)

Ten years ago,

➡ Age of son = x - 10 years.

➡ Age of man = y - 10

According to the given condition,

➡ 3(x - 10) = y - 10

➡ 3x - 30 - y + 10 = 0

➡ 3x - y = 20 ......(ii)

Subtracting (i) from (ii), we get,

➡ x = 20 years.

Therefore,

➡ y = 2x

= 40 years.

The the present ages of man and son are 40 years and 20 years respectively.

Answer:

• The present ages of man and son are 40 years and 20 years respectively.