Math, asked by zuni452, 1 month ago

The present age of a son is half the present age of his father. Ten gears age, the father was thrice as old as his son. What are their present age?

Answers

Answered by elSALSA2006
1

Answer:

The present age of son is half the present age of his father.

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

10 years ago, father's age was thrice as old as his son.

3(x - 10) = 2x - 10

3x - 30 = 2x - 10

3x - 2x = -10 + 30

x = 20

Their present ages are :-

Father's present age = 2x = 40 years

His son's present age = x = 20 years

Answered by 15833
0

Answer:

let the father's age be x

then sons age = x/2

after 10 years

sons age = x/2 + 10

fathers age= x+10

according to question

3( x/2+10) = x + 10

3x/2+30 = x+10

3x+60/2 = x +10

3x+60 = 2x+20

x = 20-60

x = -40

pls mark it as the brainliest answer

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